ax² + bx + c = 0Solution
Root 1 (x₁)—
Root 2 (x₂)—
Discriminant (D)—
Nature of Roots—
Vertex—
Axis of Symmetry—
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ax² + bx + c = 0x = (-b ± √(b² - 4ac)) / 2aThe discriminant D = b² - 4ac determines the nature of roots: D > 0 gives two distinct real roots, D = 0 gives one repeated real root, D < 0 gives two complex conjugate roots.